Rendement is actually a term
in the field of chemistry studies. The yield represents the inaccuracy of the
reaction result, which results always lower than the mathematical calculation.
For example, in a chemical reaction, should produce a substance weighing 100
grams, mathematically, but in reality the results obtained only 90 grams.
Unconsciously this also often happens in our daily live.
The mixture is a
composite of two substances or more which are not chemically united or their
constituent substances still retain their respective properties. Various
mixtures of biases are grouped into two types: homogeneous mixtures and
heterogeneous mixtures.
Actually what is
a homogeneous mixture ??? Homogeneous mixture is a mixture of two types of
substances or more that can not be seen again the boundary plane between the
substances mixed. The border field can not be visible even if viewed with a
microscope. A homogeneous mixture is often also referred to as a solution. For
example, air is a mixture of various types of gas.
While the heterogeneous mixture is a
mixture of two or more substances that still visible the boundary plane. For
example a mixture of water with oil.
The mixture is a collection of
various molecules, substances, ions, electrons, and other particles. We can
measure pressure, volume, temperature and mixed mass. We can also measure the
composition of the mixture experimentally so that the fraction of moles and
masses can be determined (Sulistiati, 2013: 39).
A mixture is classified as
heterogeneous and / homogeneous. The heterogeneous mixture is composed of
individual phases, and the observed properties are composite rather than single
phases. A homogeneous mixture comprises a single phase having properties very
different from its sole components. The solution is defined as a homogeneous
substance which is a mixture of two or more components which may be gaseous,
liquid, or solid. The gas solution is made by mixing one gas in another. Since
all the gases are mixed in all comparisons, each gas mixture is homogeneous and
it is a solution (Sastrohamidjojo, 2005: 227).
If two different substances are
inserted in one container there are 3 possibilities, which are mixed, reacted
and unmixed. If the substances are mixed, the properties of the substance are
immutable and can be separated by physical means, such as distillation,
crystallization, chromatography, and so on. On this earth rarely found pure
substance, generally a mixture. Two or more substances are called mixed, when
the particles are dispersed in the same container so that they are in contact
with each other. Two substances can be mixed when there is a reaction between
the particles. The interaction is determined by the nature and nature of the
substance. Therefore, the mixture can be divided into: a mixture of gases with
gases, gases with solid, liquid with liquid, liquid with solid, and solid with
solid (Syukri, 1999: 350-351)
3.1
Tools and materials
Tools:
1)
The vapor plate
2)
Balance Sheet
3)
Bunsen
4)
Measuring cups
5)
Glass watch
6)
Chromatographic vessel
7)
Trophy glasses
8)
Scissors
9)
Filter paper
10)
Penotol (capillary pipe)
11)
The gull
12)
Pipette drops
13)
Three-legs
14)
Gauze
Material:
1) 0.1 gram of NH4Cl
2) 0.1 gram NaCl
3) 0.1 gram of SiO2
4) 100 ml of distilled water
5) Eluen solvent = mixture of butanol, a cetic acid, water (1: 1: 4)
6) 1 gram of BaCl2
7) 25 ml of K2CrO4
8) A mixture containing BaCl2
Analysis through precipitation
A.
Percentage of chromate barium yield
1. Prepare
a cup
2. Weighed
3. Added
1 gram of BaCl2
4. Added
25 ml of distilled water
5. Stirred
until homogeneous
6. Added
2 ml of K2CrO4 0,2 M
7. Stirred
and observed precipitate formed
8. Heated
9. Filtered
with Wathman filter paper
10. Dried,
weighed, recorded the weight
11. The
theoretical results of sediment and percent yield are calculated
The
weight of the sediment BaCrO4: 4.74 grams
Percent
yield BaCrO4: 467%
Analysis through precipitation
A.
Percentage of chromate barium yield
A
mixture consists of solution, colloidal, and suspension. In the presence of
colloidal and suspension, it may allow precipitation if left long or
precipitated by K2CrO4. The data in this experiment was obtained from
experimental data in the physics physics education pgmipau 2014 report. This is
because we can not conduct the experiments caused by the power failure so we
can not do the weighing of substances and tools.
The
procedure that should be done is to weigh the cup. Then weigh the cup of the
cup containing BaCl2, which is 92.7 grams. The mass of BaCl2 is 0.7 grams. 25
ml of distilled water is added and stirred until homogeneous. Added 25 ml of
K2CrO4 0.2 M, stirred and then observed the precipitate formed. K2CrO4 is a
precipitation indicator. K2CrO4 makes the coarse particles in the mixture
precipitate and form a clear solution so that the bottom can be a precipitate
and the top can be a clear solution. When the sediment of BaCrO4 is still
formed, K2CrO4 is added again until the precipitate is no longer formed. Then
heated to boiling and filtered with Whatman filter paper. The precipitate is
dried and weighed 4.74 grams. From the data can be calculated percentage of
BaCrO4 that is 467%.
In
this experiment there may be a slight error because the yield percentage
exceeds 100%. In theory, if barium chromate is perfectly settled then the
percentage is 100%. This difference in yields may occur because of the lack of
additional K2CrO4 and in the less drying process.
How
to determine the percentage of barium chromate in the mixture ie
%
BaCrO4 = mass of sediment on practice / mass of the original example x 100%.
Analysis through precipitation
A.
Percentage of chromate barium yield
1)
Trophy weight + BaCl2 = 92.7 grams
2)
Trophy weight = 92 gram
3)
Weight BaCl2 = 1-2 = 0.7 grams
4)
The weight of the filter paper + sediment BaCrO4 = 6.48 grams
5)
The weight of filter paper = 1.74 grams
6)
Weight of sediment BaCrO4 = 4-5 = 6.48 - 1.74 = 4.74 grams
7)
Percent of results BaCrO4
A.
BaCrO4 masses theoretically
N
BaCl2 = 0.7 g / 208 = 0.0033 mol
BaCl2 + K2CrO4 → BaCrO4 +2 KCl
0.0033 mol 0.0033 mol
G BaCrO4 = mol x Mr = 0.0033 mol x 253 = 0.8349
grams
B. Percent BaCrO4 = (g theoretical precipitate) x
100%
G theoretical
= (4.74 - 0.8349) x 100%
0.8349
=
467%
please your explain a function from K2CrO4 in this experiment ! thanks
BalasHapusFunction to form precipitate BaCrO4, K2CrO4 is a precipitation indicator. K2CrO4 makes the coarse particles in the mixture precipitate and form a clear solution so that the bottom can be a precipitate and the top can be a clear solution. When the sediment of BaCrO4 is still formed, K2CrO4 is added again until the precipitate is no longer formed.
HapusHai indra.... What is the conclusion for this article.. Can you explain with your languange
BalasHapusNamely Make sediment BaCrO4 by reacting with K2CrO.
HapusThe procedure to do is weigh the cup. Then weigh a cup cup containing BaCl2, which is 92.7 grams. The mass of BaCl2 is 0.7 grams. 25 ml of distilled water is added and stirred until homogeneous. Added 25 ml of K2CrO4 0.2 M, stirred and then observed the precipitate formed. K2CrO4 is a precipitation indicator. K2CrO4 makes the coarse particles in the sediment mixture and forms a clear solution so that the bottom can be a precipitate and the top can be a clear solution. When the BaCrO4 sediment is still formed, K2CrO4 is added again until the precipitate is no longer formed. Then heated to boiling and filtered with Whatman filter paper. The precipitate was dried and weighed 4.74 grams. From the data can be calculated percentage of BaCrO4 that is 467%.
What is the benefit of rendemen?
BalasHapusRendemen useful as a comparison between the results obtained with initial simplisial, making it easier in the observation, for example yield of peanut peanut extract, sugar rendement in sugarcane and others.
HapusHow many rendement results from experimental results
BalasHapusI did a deposition experiment ,The precipitate is dried and weighed 4.74 grams. From the data can be calculated percentage of BaCrO4 that is 467%.
HapusIn this experiment there may be a slight error because the yield percentage exceeds 100%. In theory, if barium chromate is perfectly settled then the percentage is 100%. This difference in yields may occur because of the lack of additional K2CrO4 and in the less drying process.
How to determine the percentage of barium chromate in the mixture ie
% BaCrO4 = mass of sediment on practice / mass of the original example x 100%.